思路:单调递增栈 + k 控制删除次数。高位越小整体越小,遇更小数字时弹出栈顶大数(仅当 k0);栈空且当前为 0 则跳过(避免前导零);若遍历完 k 仍0,从末尾再删 k 位。
Гангстер одним ударом расправился с туристом в Таиланде и попал на видео18:08
,这一点在safew官方版本下载中也有详细论述
He also told Ball he may go back into the recording studio to work on "some things that are half-formed or were never finished".
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